Gerd Faltings, who proved the Mordell conjecture, wins the Abel Prize

(scientificamerican.com)

46 points | by digital55 4 days ago

4 comments

  • nhatcher 4 days ago
    Oh wow! I wouldn't have expected this so many years later. Mordel's conjecture implies asva special case that for all n>=4 there are only a finite number of solutions to Fermat's equations with relative prime numbers. Brings me back!
  • 011101101 6 hours ago
    A point is that which has no breadth.

    The line is a breadthless legth.

    Mordell conjecture is that only circles or figure contain infinite points, whereas curves with exponents over 3 are finite accumulations.

  • ljsprague 5 hours ago
    "He proved that if a curve’s equation has a variable raised to a power higher than 3, then it must have a finite number of [rational] points."
    • OgsyedIE 2 hours ago
      This must be an incorrect description of what has actually been proved, since x^4 is a counterexample.
      • raphlinus 1 hour ago
        My understanding, which is to be taken with a grain of salt, is that there's an additional constraint, not stated in the Scientific American article, that the plane curve be irreducible. The example of x^4 is reducible, it's x^2 * x^2 among other thing. The actual conjecture is expressed in terms of genus, but this follows from the genus-degree formula.
        • thornhill 1 hour ago
          The curve they mean y = x^4 is irreducible but the genus is 0 since it’s isomorphic to the affine line.
  • RonSFriedman86 4 days ago
    [dead]